This line is almost forced with draw as final result.
The neat idea with h4/h3 maneuver is that black can choose to capture either e3 or g3 pawn.
Which pawn is the correct one to capture?
Both alternatives appear adequately enough to secure the draw, i can't identify any major differences. Still i prefer Bxe3 as the bad bishop (big pawn) capture towards the center as per rule of thumb.
[d]5k2/1p4p1/pP3p2/4p3/8/P3P1P1/3B1bK1/8 b - - 0 8
--------------------------------------------
[pgn][Event "?"]
[Site "?"]
[Date "????.??.??"]
[Round "?"]
[White "New game"]
[Black "?"]
[Result "*"]
[SetUp "1"]
[FEN "5k2/pp4pp/4pp2/1P6/8/P2KP1P1/5P1b/2B5 b - - 0 1"]
[PlyCount "15"]
1... h5 2. Ke2 a6 3. b6 h4 4. Kf3 h3 5. Kg4 Bg1 6. Kxh3 Bxf2 7. Bd2 e5 8. Kg2
Bxg3 (8... Bxe3 9. Bxe3) *
[/pgn]
[pgn][Event "Blitz 1m"]
[Site "?"]
[Date "????.??.??"]
[Round "?"]
[White "Stockfish 100616 64 BMI2"]
[Black "Kajapix"]
[Result "*"]
[SetUp "1"]
[FEN "5k2/pp4pp/4pp2/1P6/8/P2KP1P1/5P1b/2B5 b - - 0 1"]
[PlyCount "5"]
[TimeControl "60"]
{4096MB, , EXPERT-PC} 1... h5 2. Ke2 a6 (2... Ke7 3. Kf3 Kd6 4. Kg2 Bxg3 5. b6
(5. Kxg3 Kc5 (5... Kd5 6. a4 g5 7. Ba3 e5 8. Be7 Ke6 9. Bc5 a6 $11)) 5... a6 6.
Kxg3 e5 7. Kh4 g6 8. Bd2 Kd5 $11) 3. bxa6 (3. b6 h4 4. Kf3 h3 5. Kg4 Bg1 6.
Kxh3 Bxf2 7. Bd2 e5 8. Kg2 Bxg3 {0} (8... Bxe3 9. Bxe3 $11) 9. Kxg3 $11 {
1.36/30 1}) (3. a4 h4 4. Kf3 axb5 5. axb5 h3 6. Kg4 Bg1 7. Kxh3 Bxf2 8. Bd2 Kf7
$6 (8... Ke7 $11)) 3... bxa6 $11 *
[/pgn]
Code: Select all
[Event "Blitz 1m"]
[Site "?"]
[Date "????.??.??"]
[Round "?"]
[White "Stockfish 100616 64 BMI2"]
[Black "Kajapix"]
[Result "*"]
[SetUp "1"]
[FEN "5k2/pp4pp/4pp2/1P6/8/P2KP1P1/5P1b/2B5 b - - 0 1"]
[PlyCount "5"]
[TimeControl "60"]
{4096MB, , EXPERT-PC} 1... h5 2. Ke2 a6 (2... Ke7 3. Kf3 Kd6 4. Kg2 Bxg3 5. b6
(5. Kxg3 Kc5 (5... Kd5 6. a4 g5 7. Ba3 e5 8. Be7 Ke6 9. Bc5 a6 $11)) 5... a6 6.
Kxg3 e5 7. Kh4 g6 8. Bd2 Kd5 $11) 3. bxa6 (3. b6 h4 4. Kf3 h3 5. Kg4 Bg1 6.
Kxh3 Bxf2 7. Bd2 e5 8. Kg2 Bxg3 {0} (8... Bxe3 9. Bxe3 $11) 9. Kxg3 $11 {
1.36/30 1}) (3. a4 h4 4. Kf3 axb5 5. axb5 h3 6. Kg4 Bg1 7. Kxh3 Bxf2 8. Bd2 Kf7
$6 (8... Ke7 $11)) 3... bxa6 $11 *